Simulation of the relationship between input factors and output indicators of the internal grinding process, considering the mutual vibrations of the tool and the workpiece

OBRABOTKAMETALLOV technology Vol. 25 No. 1 2023 where ωTS is a system compliance; ωTS = 30·10 -9 m·N; DP y is increment of the normal component of the cutting force; DPy ≥ 0. Let’s assume that there is no increment of the normal component of the cutting force at the first revolution DPy = 0, therefore, after substituting the parameter values into the formula, we get: 1 0 y A D = , m 3) Calculate the depth of micro-cutting. On the previous revolution, there is no radial removal of the material Dr0 = 0. Given the assumption that the wear of the grinding wheel on the first revolution is equal to zero, DR1 = 0, then the equation (1) is defined as: 6 1 1 15 10 f A t - D = D = ⋅ , m From here, the value of the depth of micro-cutting is calculated: 6 6 1 1 1 0 15 10 15 10 f y f t S t - - = + D = + ⋅ = ⋅ , m 4) At the current revolution, the value of the radial removal of the material can be determined by the equation: 2 0,4 7 13 15 3 ( ) fi i u fi c k u g e g t r V t K V V n D ω D = p p + + Y + r , (3) where Kc – chip formation coefficient, Kc = 0.85; Vu – the speed of rotation of the workpiece, m/s; Vk – the speed of rotation of the wheel, m/s; ng – number of grains per unit area, pcs/m2; r g – corner radius the grain vertex, m; De – equivalent diameter, m. The equivalent diameter is calculated by the equation: e D d D D d ⋅ = - , (4) where D – diameter of the grinding wheel, m; d – the diameter of the workpiece, m. After substituting the data into equation (4), we get: 150 60 0.1 150 60 e D ⋅ = = - , m. The value of the variable Y it will be calculated depending on the initial phase of the deviations. For yy = 0×(2p) and yy = p: 2 2 2 3 2 0,5 1,5 3 2 15 2 sin 1 2 15 sin 2 15 sin 15 16 32 2 2 u f u u f e e e A V t A V A V A t D D D ω ω ω ω    γ     -      γ γ   Y = + + + ω ω ω or 2 2 2 3 2 0,5 1,5 3 2 15 1 sin ( ) 15 sin 2 15 sin 15 16 32 2 2 u f u u f e e e A V t A V A V A t D D D ω ω ω ω - γ γ γ Y = + + + ω ω ω , If yy = p/2 and yy = 3p/2: 2 2 0,5 15 sin 2 15 16 32 u f e A V A t D ω ω γ Y = - ω ,

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