OBRABOTKAMETALLOV technology Vol. 25 No. 1 2023 The amount of material removal will be: 6 2 6 1 0,4 6 12 6 6 (14.91 10 ) 5.844 10 7 13 0.25 14.91 10 0.17 10 15 3 0.85 (35 0.25) 15.866 10 0.1 7.31 10 r - - ω - - - ⋅ D = = ⋅ p p ⋅ + + ⋅ ⋅ + ⋅ ⋅ ⋅ ⋅ , m The thickness of the layer in which the roughness is distributed: 6 6 6 1 1 1 14.91 10 5.844 10 9.069 10 f H t r - - - ω = - D = ⋅ - ⋅ = ⋅ , m The cutting load: 3 6 6 6 6 1 3 2 25 10 15.866 10 7.31 10 10 10 9.069 10 0.1 y P - - - - = ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ × 6 6 6 8 0.3746 0.055 9.069 10 0.061 7.31 10 10 10 13.33 10 2.884 0.5591 - - - × ⋅ ⋅ + ⋅ ⋅ ⋅ ⋅ = , N. 8) The distance from the deepest valley to the midline of the profile is calculated according to: 2 fi i mi t r W ω - D = . (8) Insert numeric values into the equation (8): 6 6 6 1 14.91 10 5.844 10 4.535 10 2 m W - - - ⋅ - ⋅ = = ⋅ , m One of the final stages of calculating the parameters of the revolution under consideration is the comparison of the value Wm1 with the amount of Drω1, 1 1 m W rω ≤ D 4.535 × 10–6 ≤ 5.844 · 10–6. Due to the fact that the value of Drω1 exceeds the value of Wm1, then the value of the arithmetic mean length of the profile Ra is determined as: 0.4 0.6 1 0.4 0.4 0.2 0.2 0,4 6 0.6 6 0.4 0.4 6 2 6 2 0.25 ( ) 0.25 0.25 (14.91 10 ) 1.041 10 . 0.85 (0.25 35) (15.866 10 ) 0.1 (7.31 10 ) u f a c u k g e g V t R K V V n D - - - = = + r ⋅ ⋅ = = ⋅ + ⋅ ⋅ ⋅ Second revolution. 1) Find the sum of the parameters of preload and transverse feed: 6 6 6 2 5 10 10 10 15 10 y A S N - - - D = + = ⋅ + ⋅ = ⋅ , m. 2) Determine the depth of micro-cutting: 6 6 6 2 1 5 10 14.91 10 19.91 10 f y f t S t - - - = + = ⋅ + ⋅ = ⋅ , m.
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